Merge two nodes in XSL

Question

I have some trouble with XSLT.

We have two nodes, like:

<main>
  <part>
    <block>1</block>
    <block>2</block>
    <block>3</block>
    <block>4</block>
  </part>
  <article>
    <block>A</block>
    <block>B</block>
    <block>B</block>
    <block>D</block>
  </article>
</main>

I need to view

<li>1</li>
<li>A</li>
<li>2</li>
<li>B</li>
<li>3</li>
<li>C</li>
<li>4</li>
<li>D</li>

At this moment wrote this, but it does not work as need:

<xsl:for-each select="part/*|article/*">
   <xsl:choose>                                     
      <xsl:when test="position() mod 2 = 0">
         <li><xsl:value-of select="."/></li>                                           
      </xsl:when>
   </xsl:choose>
</xsl:for-each>

Help me please.

Answer 1

Here's a very simple way to look at it:

XSLT 1.0

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:template match="/">
    <ul>
        <xsl:for-each select="main/part/block">
        <xsl:variable name="i" select="position()" />
            <li><xsl:value-of select="."/></li>
            <li><xsl:value-of select="../../article/block[$i]"/></li>
        </xsl:for-each>
    </ul> 
</xsl:template>

</xsl:stylesheet>