Sound's like after doing std::copy()
with std::cin
leaves the input stream in failed state after (which is OK, otherwise the copy loop wouldn't end).
Put a
std::cin.clear();
after this line (also see std::istream::clear()
).
문제
My main.cpp
calls two functions for sorting of integers, given by user at stdin
.
Problem:: Call to SortIteratorAdaptor()
works perfectly but then exits without waiting for user's input in SortVector()
. I think, this happens due to EOF
lying at stdin
which makes the second std::cin
to exit without waiting for user's input. If this is the case, what would be the best way to consume EOF
at `stdin?
#include <iostream>
#include <vector>
#include <iterator>
#include <algorithm>
void SortIteratorAdaptor( void )
{
std::vector<int> v ;
std::cout << "Enter SortIterator Elems\n" ;
std::copy(std::istream_iterator<int> (std::cin),std::istream_iterator<int> (),\
std::back_insert_iterator<std::vector<int> > (v) ) ;
std::sort( v.begin(), v.end() ) ;
std::cout << "Sorted Elems Are:\n" ;
std::copy( v.begin(), v.end(), std::ostream_iterator<int> (std::cout, "\n") ) ;
return ;
}
void SortVector( void )
{
std::vector<int> v ;
int n = 0 ;
std::cout << "Enter Vector elements, Press Ctrl+D to break std::cin\n" ;
while( std::cin >> n ) v.push_back( n ) ;
std::cout << "\n" << "Sorted Elems Are:\n" ;
std::sort( v.begin(), v.end() ) ;
for( n = 0; n < v.size(); n++ ) std::cout << v[n] << "\n" ;
std::cout << "\n\n" ;
return ;
}
int main( int argc, char** argv )
{
std::cout << "Begin Sort Ints with Iterator_Adaptors and vectors\n" ;
SortIteratorAdaptor() ;
std::cout << "Begin Sort Ints with vectors\n" ;
SortVector() ;
std::cout << "Exiting..." ;
return 0 ;
}
해결책
Sound's like after doing std::copy()
with std::cin
leaves the input stream in failed state after (which is OK, otherwise the copy loop wouldn't end).
Put a
std::cin.clear();
after this line (also see std::istream::clear()
).