The reference to the current object is implicitly a reference to a superclass as well (as it extends it).
So you should be able to do
Generic g = new Generic(this);
문제
I have 3 classes:
class Superclass
...
public class Generic{
public Generic(Superclass s){...}
}
And a subclass extending Superclass
class SubClass extends Superclass{
public void methodM(){
Generic g = new Generic(???);
...
}
}
In methodM
I use the constructor Generic
and I want to pass a reference to the Superclass instance extended by Subclass. So I don't want to do something like new Generic(new Superclass)
, rather something like: new Generic(super.IdontKnowWhat)
thank you
해결책
The reference to the current object is implicitly a reference to a superclass as well (as it extends it).
So you should be able to do
Generic g = new Generic(this);
다른 팁
Just call it as super.parameter
as super is an inbuilt keyword used to reference the super class fields. You can read about super
in the java docs tutorial for super.
U can pass the reference of the subclass as it extends the superclass.. But it depends on what methods u want to acssess..If u pass reference of subclass then u should acssess the methods of subclass through the object received in constructor of Generic class.. So u should construct the new object of superclass in case u want to acssess methods of superclass..