Cut for variable delimiter - Bash [duplicate]

Question

This question already has answers here:

How to find the last field using 'cut' (14 answers)

Closed 2 years ago.

I want to get the second column of a file where separator between column 1 and column 2 is of variable length. For example:

A1_KOG1494_________AAMFAARSFSERK
A2_KOG1494_______AAKFALRSFSERK
A3_KOG1494___________AAKFALRSFSCCK

Thank's for your help

Answer 1

You can use awk with custom field separator:

s='A1_KOG1494_________AAMFAARSFSERK'
awk -F '_{2,}' '{print $2}' <<< "$s"
AAMFAARSFSERK

awk -F '_' '{print $NF}' <<< "$s"
AAMFAARSFSERK

Another example:

awk -F '_{2,}' '{print $2}' <<< "A3_KOG1494___________AAKFALRSFSCCK"
AAKFALRSFSCCK