문제

I am making a c insertion sort and it works fine except that after the sort the first number is always a weird negative number and the program errors out.

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

void insertionSort(int list[], int last){
     int hold;
     int walker;
     int current;
     int count;

     count = 0;
     for (current = 1; current <= last; current++){
         hold = list[current];
         for (walker = current - 1; 
             walker >= 0 && hold < list[walker]; walker--){
                    list[walker + 1] = list[walker];
             }
         list [walker + 1] = hold;
         count++;
     }
     printf("\n\nHow many passes to sort?\n%d\n\n", count);
     return;
}

int main(int argc, char *argv[])
{
  int numbers[100];
  int i;

  srand(time(NULL));
  for (i = 0; i < 100; i++){
      numbers[i] = rand() % 100;
  }
  printf("Unsorted Numbers\n-------- -------\n");
  for (i = 0; i < 100; i++){
      printf("%d,", numbers[i]);
  }
  insertionSort(numbers, 100);
  printf("\nSorted Numbers\n-------- -------\n");
  for (i = 0; i < 100; i++){
      printf("%d,", numbers[i]);
  }
  system("PAUSE");  
  return 0;
}
도움이 되었습니까?

해결책

You are going OVER the array size within the loop. When current = last, list[last] is list[100], the 101th element of the array... this is also not good.

Edit. I just tested this out and it worked for me. Only thing i changed was the <= in the outer loop to n <

void insertionSort(int list[], int last){
 int hold;
 int walker;
 int current;
 int count;

 count = 0;
 for (current = 1; current < last; current++){
     hold = list[current];
     for (walker = current - 1; 
         walker >= 0 && hold < list[walker]; walker--){
                list[walker + 1] = list[walker];
         }
     list [walker + 1] = hold;
     count++;
 }
 printf("\n\nHow many passes to sort?\n%d\n\n", count);
 return;
}

다른 팁

If you declare an array like

int numbers[100]

numbers[99] is the last element. In your sort function you are accessing numbers[100] as well.

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