Bash command substution error
문제
The code:
`cat <(fgrep -i -v "$DAEMON_TEST" <(sudo -u asm crontab -l)) <(echo "$CRON") | sudo -u asm crontab -`
The error:
command substitution: line 46: syntax error near unexpected token `('
/etc/init.d/asm: command substitution: line 46: `cat <(fgrep -i -v "$DAEMON_TEST" <(sudo -u asm crontab -l)) <(echo "$CRON") | sudo -u asm crontab -'
The command runs fine when run directly into the shell by replacing the variables with the relevant strings
Here are the variables:
DAEMON_TEST=asm_test.php
CRON="*/15 * * * * /opt/asm/daemons/test.php"
해결책
The issue ended up being completely unrelated.
Changed:
#/bin/sh
to:
#/bin/bash
I never realized there would be a differnce
https://superuser.com/questions/125728/what-is-the-difference-between-bash-and-sh
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