Ebean + Play 2.0 Queries
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26-05-2021 - |
문제
When I have:
public class User extends Model {
@Id
public Long id;
@Constraints.Required
@Formats.NonEmpty
public String username;
public String firstName; public String lastName;
can I do User.find.byUsername("myusername")
or User.find.byFirstNameAndLastName...
or would I have to define the method in the User class?
Thank you!
해결책
There is no "magic" method in PlayFramework2 (ok, in reality there is just "less" magic methods)
So you need to define these functions, or to use a composed statement.
User.find.where().eq("username", myUserName).findUnique()
User.find.where().eq("firstname", firstname).eq("lastname", lastname).findList()
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