C++ print value of a pointer
문제
I have an array of double pointers, but every time I try do print one of the values the address gets printed. How do I print the actual value?
cout << arr[i] ? cout << &arr[i] ? they both print the address
Does anyone know?
해결책
If it's really an array of (initialized) double pointers, i.e.:
double *arr[] = ...
// Initialize individual values
all you need is:
cout << *arr[i];
다른 팁
cout << *(arr[i]) will print the value.
cout << *(arr[i]);
If "arr" is declared as
double* arr[..];
Then you would use:
cout << *(arr[i])
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