What Does Adding One to a Character Array in C Do?
문제
I'm looking through some code for learning purposes. I'm working through this portion of code.
// e.g. const unsigned char data={0x1,0x7C ... }
unsigned char buf[40];
memset(buf,0,40);
buf[0] = 0x52;
memcpy(buf+1, data, length); // What does buf+1 do in this situation?
On the last line where memcpy is called what does buf+1 do? buf is a character array, so what does +1 do to it?
해결책
In C, every array name is a pointer, so buf here also means the pointer which point to buf[0].Then "buf+1" means "buf[1]"'s address.
다른 팁
buf+1
is equivalent to &(buf[1])
buf+1
is the same as &(buf[1])
. In other words, it returns a pointer to the 2nd (index 1) character of buf.
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