문제

I'd like to have the dimensions labeled in my xtable output. However, the table method of xtable does not output dimension labels even when I specify them manually to table:

set.seed(10)
d <- data.frame(x=sample(1:4),y=sample(1:4))
tb <- with(d, table(d,dnn=c("Xs","Ys")))
> tb
   Ys
Xs  1 2 3 4
  1 0 0 0 1
  2 0 1 0 0
  3 1 0 0 0
  4 0 0 1 0
> xtable(tb)
% latex table generated in R 2.15.1 by xtable 1.7-0 package
% Tue Oct  9 09:06:10 2012
\begin{table}[ht]
\begin{center}
\begin{tabular}{rrrrr}
  \hline
 & 1 & 2 & 3 & 4 \\ 
  \hline
1 &   0 &   0 &   0 &   1 \\ 
  2 &   0 &   1 &   0 &   0 \\ 
  3 &   1 &   0 &   0 &   0 \\ 
  4 &   0 &   0 &   1 &   0 \\ 
   \hline
\end{tabular}
\end{center}
\end{table}

Inspection of the code for xtable.table doesn't yield any secrets. Short of building them manually with multirow is there any way of getting the dimensions labeled?

도움이 되었습니까?

해결책

One solution with the tables package:

library(tables) 

tblr <- tabular((Xs = as.factor(x)) ~ (Ys = as.factor(y)), data = d)
latex(tblr)

\begin{tabular}{lcccc}
\hline
 & \multicolumn{4}{c}{Ys} \\ 
Xs  & 1 & 2 & 3 & \multicolumn{1}{c}{4} \\ 
\hline
1  & $0$ & $0$ & $0$ & $1$ \\
2  & $0$ & $1$ & $0$ & $0$ \\
3  & $1$ & $0$ & $0$ & $0$ \\
4  & $0$ & $0$ & $1$ & $0$ \\
\hline 
\end{tabular}

다른 팁

This doesn't create multirow or multicolumn headers based on the names of the dimensions, but it at least does get them displayed.

print(xtable(format(ftable(tb))), 
      include.rownames=FALSE, include.colnames=FALSE,
      sanitize.text.function = function(x) {gsub('"',"",x)})

which gives

% latex table generated in R 2.15.1 by xtable 1.7-0 package
% Tue Oct 09 11:28:33 2012
\begin{table}[ht]
\begin{center}
\begin{tabular}{llllll}
  \hline
  \hline
     & Ys & 1 & 2 & 3 & 4 \\ 
  Xs &      &     &     &     &     \\ 
  1  &      &   0 &   0 &   0 &   1 \\ 
  2  &      &   0 &   1 &   0 &   0 \\ 
  3  &      &   1 &   0 &   0 &   0 \\ 
  4  &      &   0 &   0 &   1 &   0 \\ 
   \hline
\end{tabular}
\end{center}
\end{table}

You can restore the horizontal lines in the "right" place as well:

print(xtable(format(ftable(tb))), 
      include.rownames=FALSE, include.colnames=FALSE,
      sanitize.text.function = function(x) {gsub('"',"",x)},
      hline.after = c(-1, 2, nrow(tb)+2))

giving

% latex table generated in R 2.15.1 by xtable 1.7-0 package
% Tue Oct 09 11:29:21 2012
\begin{table}[ht]
\begin{center}
\begin{tabular}{llllll}
  \hline
      & Ys & 1 & 2 & 3 & 4 \\ 
  Xs &      &     &     &     &     \\ 
   \hline
1  &      &   0 &   0 &   0 &   1 \\ 
  2  &      &   0 &   1 &   0 &   0 \\ 
  3  &      &   1 &   0 &   0 &   0 \\ 
  4  &      &   0 &   0 &   1 &   0 \\ 
   \hline
\end{tabular}
\end{center}
\end{table}
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