init.d script for running second mysql server fails [closed]

Question

Closed. This question is off-topic. It is not currently accepting answers.

---

Want to improve this question? Update the question so it's on-topic for Stack Overflow.

Closed 8 years ago.

Improve this question

I have 2 mysql servers, one is set with all the mysql defaults (port,socket, etc.) and the second is set to port 3307 and a different socket with defaults file called my-dev.cnf .

when i run:

/usr/bin/mysqld_safe --defaults-file=/etc/my-dev.cnf 

the server runs correctly

what i'm trying to do, is to have an init.d script to run it. I copied the /etc/init.d/mysqld script and changed the following line:

exec="/usr/bin/mysqld_safe"

to:

exec="/usr/bin/mysqld_safe --defaults-file=/etc/my-dev.cnf"

but it keeps failing on:

[ -x $exec ] || exit 5

with:

/etc/init.d/mysql-dev: line 63: [: '/usr/bin/mysqld_safe': binary operator expected

how can i make it work so it will use the defaults i set in /etc/my-dev.cnf?

thanks!

Answer 1

The problem is that [ -x ] is testing if a file is executable, but the string is not an executable, it's your modified command line.

Paste the whole script on http://pastie.org , I will adapt it ;)