문제

Using java.util.regex (jdk 1.6), the regular expression 201210(\d{5,5})Test applied to the subject string 20121000002Test only captures group(0) and does not capture group(1) (the pattern 00002) as it should, given the code below:

Pattern p1 = Pattern.compile("201210(\\d{5,5})Test");
Matcher m1 = p1.matcher("20121000002Test");

if(m1.find()){

    for(int i = 1; i<m1.groupCount(); i++){         
    System.out.println("number = "+m1.group(i));            
    }
}

Curiously, another similar regular expression like 201210(\d{5,5})Test(\d{1,10}) applied to the subject string 20121000002Test0000000099 captures group 0 and 1 but not group 2.

On the contrary, by using JavaScript's RegExp object, the exact same regular expressions applied to the exact same subject strings captures all groups, as one could expect. I checked and re-checked this fact on my own by using these online testers:

Am I doing something wrong here? Or is it that Java's regex library really sucks?

도움이 되었습니까?

해결책

m1.groupCount() returns the number of capturing groups, ie. 1 in your first case so you won't enter in this loop for(int i = 1; i<m1.groupCount(); i++)

It should be for(int i = 1; i<=m1.groupCount(); i++)

다른 팁

Change the line

for(int i = 1; i<m1.groupCount(); i++){     

to

for(int i = 1; i<=m1.groupCount(); i++){      //NOTE THE = ADDED HERE    

It now works as a charm!

From java.util.regex.MatchResult.groupCount:

Group zero denotes the entire pattern by convention. It is not included in this count.

So iterate through groupCount() + 1.

the regular expression "201210(\d{5,5})Test" applied to the subject string "20121000002Test" only captures group(0) and does not capture group(1)

Well I can say I didn't read the manual either but if you do it says for Matcher.groupCount()

Returns the number of capturing groups in this matcher's pattern. Group zero denotes the entire pattern by convention. It is not included in this count.

for (int i = 1; i <= m1.groupCount(); i++) { 
                   ↑
              your problem
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