문제

I have a genericised class that I wish to subclass as follows:

public class SomeTable<T extends BaseTableEntry>
    extends BaseTable<T>
{

    public SomeTable(int rows, int cols)
    {
        super(rows, cols, SomeTableEntry.class);
        //Does not compile:
        //Cannot find symbol: constructor BaseTable(int, int, java.lang.Class<blah.blah.SomeTableEntry.class>)
    }
}

... where the genericised superclass is:

public class BaseTable<T extends BaseTableEntry>
{

    public BaseTable(int rows, int cols, Class<T> clasz)
    {
        ...
    }
...
}

I understand the compiler error, but cannot seem to find a workaround, other than to include an extra parameter in the SomeTable constructor.

Any suggestions?

Thanks!

도움이 되었습니까?

해결책

This compiles:

public class SomeTable extends BaseTable<SomeTableEntry> {
    public SomeTable(int rows, int cols)
    {
        super(rows, cols, SomeTableEntry.class);
    }
}

It works with a cast:

public class SomeTable<T extends BaseTableEntry> extends BaseTable<T> {
    public SomeTable(int rows, int cols)
    {
        super(rows, cols, (Class<T>)SomeTableEntry.class);
    }
}

but I'm looking forward to someone posting the explanation for why the compiler requires the cast for the class.

다른 팁

It is possible to define the SomeTable constructor generically if you pass Class to it the same way as you do with the base class:

public class BaseTable<T extends BaseTableEntry>
{
    public BaseTable(int rows, int cols, Class<? extends T> clazz)
    {
        // ...
    }
}

class SomeTable<T extends BaseTableEntry>
extends BaseTable<T>
{
    public SomeTable(int rows, int cols, Class<? extends T> clazz)
    {
        super(rows, cols, clazz);
    }
}
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