문제
다음 형식으로 응답 XML을 받고 싶습니다 ...
<PersonDetails>
<Name>Ajay</Name>
<Age>29</Age>
<ContactDetails>
<ContactDetail>
<ContactType>Mobile</ContactType>
<ContactValue>9565649556</ContactValue>
</ContactDetail>
<ContactDetail>
<ContactType>Email</ContactType>
<ContactValue>ajay@yahoo.com</ContactValue>
</ContactDetail>
</ContactDetails>
</PersonDetails>
여기에는 두 가지 다른 선택 문장이 있습니다 ...
SELECT name, age FROM Person_Details
WHERE id = 12
SELECT Contact_Type, Contact_Value FROM Person_Contact_Details
Where id = 12
여기에 모든 제안이 ... XML Explicit/Path의 조합으로 시도했습니다.
해결책
PATH
:
SELECT name AS Name
, age AS Age
, (SELECT Contact_Type AS ContactType
, Contact_Value AS ContactValue
FROM Person_Contact_Details c
WHERE c.id = p.id
FOR XML PATH('ContactDetail'), TYPE) AS ContactDetails
FROM Person_Details p
WHERE id = 12
FOR XML PATH('PersonDetails')
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