How can I use PHP to list all the dates in a year?
문제
I'm trying to use PHP to create a script that searches all the days between now and one year's time and lists all the dates for Fridays and Saturdays. I was trying to use PHP's date() and mktime() functions but can't think of a way of doing this. Is it possible?
Thanks, Ben
해결책
Here's how to do it in a cool way, with special thanks to strtotime
's relative formats.
$friday = strtotime('Next Friday', time());
$saturday = strtotime('Next Saturday', time());
$friday = strtotime('+1 Week', $friday);
$saturday = strtotime('+1 Week', $saturday);
Of course you should tweak it to do exactly what you want, but that's beside the point I was trying to make.
Also note that strtotime
will give you timestamps. To find out the date use:
date('Y-m-d', $friday)
Another thing to know is that Next <dayofweek>
will exclude your current day from the search, so if you also want to include the current day you can do it like this:
$friday = strtotime('Next Friday', strtotime('-1 Day', time()));
And here's a full working script that does exactly what you wanted.
<?php
// prevent multiple calls by retrieving time once //
$now = time();
$aYearLater = strtotime('+1 Year', $now);
// fill this with dates //
$allDates = Array();
// init with next friday and saturday //
$friday = strtotime('Next Friday', strtotime('-1 Day', $now));
$saturday = strtotime('Next Saturday', strtotime('-1 Day', $now));
// keep adding days untill a year has passed //
while(1){
if($friday > $aYearLater)
break 1;
$allDates[] = date('Y-m-d', $friday);
if($saturday > $aYearLater)
break 1;
$allDates[] = date('Y-m-d', $saturday);
$friday = strtotime('+1 Week', $friday);
$saturday = strtotime('+1 Week', $saturday);
}
//XXX: debug
var_dump($allDates);
?>
Good luck, Alin
다른 팁
With DateTime objects:
<?php
define('FRIDAY', 5);
define('SATURDAY', 6);
$from = new DateTime;
$to = new DateTime('+1 year');
for($date=clone $from; $date<$to; $date->modify('+1 day')){
switch($date->format('w')){
case FRIDAY:
case SATURDAY:
echo $date->format('r') . PHP_EOL;
}
}
Update: I've added the $date=clone $from
part to remark that objects in PHP/5 are no longer copied with the =
operator but referenced.
$secondsperday=86400;
$firstdayofyear=mktime(12,0,0,1,1,2010);
$lastdayofyear=mktime(12,0,0,12,31,2010);
$theday = $firstdayofyear;
for($theday=$firstdayofyear; $theday<=$lastdayofyear; $theday+=$secondsperday) {
$dayinfo=getdate($theday);
if($dayinfo['wday']==5 or $dayinfo['wday']==6) {
print $dayinfo['weekday'].' '.date('Y-m-d',$theday)."<br />";
}
}
$number_of_days_from_now = 365;
$now = time();
$arr_days = array();
$i = 0;
while($i <> $number_of_days_from_now){
$str_stamp = "- $i day";
$arr_days[] = date('Y-m-d',strtotime($str_stamp,$now));
$i ++;
}
var_dump($arr_days);
I did something similar to the accepted answer that didn't suited to me