문제

Is it possible to return to my app once a phone link (tel:) has been clicked, and opened using

[[UIApplication sharedApplication] openURL:xyz]

For example, when the user ends the call?

Thanks

도움이 되었습니까?

해결책

No. Although if you store your state using NSUserDefaults (or other means) you can return to the same point where you left; the user will have to relaunch your app to do this. This approach is recommended in the Human Interface Guidelines.

다른 팁

No, unfortunately there is no way to achieve this, since clicking a link will always first terminate your app and then start the new one.

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