How do I store a mongojs query result to a variable [duplicate]

Question

This question already has answers here:

How to return the response from an asynchronous call (43 answers)

Closed 4 years ago.

All i get from this code:

var views = db.books.find({"number":1}, {"views":1, _id:0}); console.log(views);

is this response:

{ _readableState:
  { highWaterMark: 16384,
    buffer: [],
    length: 0,
    pipes: null,
    pipesCount: 0,
    flowing: false,
    ended: false,
    endEmitted: false,
    reading: false,
    calledRead: false,
    sync: true,
    needReadable: false,
    emittedReadable: false,
    readableListening: false,
    objectMode: true,
    defaultEncoding: 'utf8',
    ranOut: false,
    awaitDrain: 0,
    readingMore: false,
    decoder: null,
    encoding: null },
 readable: true,
 domain: null,
 _events: {},
 _maxListeners: 10,
 _get: [Function] }

Answer 1

You can use .findOne to return a single instance and get the result.

Find assumes you're querying for a collection of documents and return a cursor:

You can for example, convert it to an array:

db.books.find({"number":1}, {"views":1, _id:0}).toArray(function(err, results){
    console.log(results);
});

You can use .each to iterate through elements and .nextObject to get the next, they're all asynchronous obviously being IO operations in nodejs, here is the section on cursors in the manual.