문제

I need to display and handle UTC dates in the following format:

2013-06-28T22:15:00Z

As this format is part of the ISO8601 standard I have no trouble creating DateTime objects from strings like the one above. However I can't find a clean way (meaning no string manipulations like substr and replace, etc.) to present my DateTime object in the desired format. I tried to tweak the server and php datetime settings, with little success. I always get:

$date->format(DateTime::ISO8601); // gives 2013-06-28T22:15:00+00:00

Is there any date format or configuration setting that will give me the desired string? Or I'll have to append the 'Z' manually to a custom time format?

도움이 되었습니까?

해결책

No, there is no special constant for the desired format. I would use:

$date->format('Y-m-d\TH:i:s\Z');

But you will have to make sure that the times you are using are really UTC to avoid interpretation errors in your application.

다른 팁

If you are using Carbon then the method is:

echo $dt->toIso8601ZuluString();    
// 2019-02-01T03:45:27Z

In order to get the UTC date in the desired format, you can use something like this:

gmdate('Y-m-d\TH:i:s\Z', $date->format('U'));

In PHP 8 the format character p was added:

$timestamp = new DateTimeImmutable('2013-06-28T22:15:00Z');
echo $timestamp->format('Y-m-d\TH:i:sp');
// 2013-06-28T22:15:00Z

To do this with the object-oriented style date object you need to first set the timezone to UTC, and then output the date:

function dateTo8601Zulu(\DateTimeInterface $date):string {
  return (clone $date)
    ->setTimezone(new \DateTimeZone('UTC'))
    ->format('Y-m-d\TH:i:s\Z');
}

Edit: clone object before changing timezone.

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