You can use strconv.Atoi
which wraps strconv.ParseInt
in a way you want.
Idiomatic way to use strconv.ParseInt with ints
문제
I end up writing code like this. I need a regular int (for some other function call), but parseInt only produces 64 bit ints:
i64, err := strconv.ParseInt(s, 10, 0)
if err != nil {
fmt.Println("parsing failed for", s)
}
i := int(i64)
http://play.golang.org/p/_efRm7yp3o
Is there a way to avoid the extra cast? Or a way to make this more idiomatic?
해결책
다른 팁
Use the bitSize parameter
of strconv.ParseInt
package main
import (
"fmt"
"strconv"
)
// 32 or 64 depending on platform
const IntBits = 1 << (^uint(0)>>32&1 + ^uint(0)>>16&1 + ^uint(0)>>8&1 + 3)
func printInt(i int) {
fmt.Println(i)
}
func main() {
s := "-123123112323231231"
i64, err := strconv.ParseInt(s, 10, IntBits)
if err != nil {
fmt.Println("parsing failed for ", s)
}
i := int(i64)
printInt(i)
i64, err = strconv.ParseInt(s, 10, 32)
if err != nil {
fmt.Println("parsing failed for ", s)
}
i = int(i64)
printInt(i)
}
Output
-123123112323231231
parsing failed for -123123112323231231
-2147483648
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