문제

I would like to generate in Python or C the Cantor ternary set with help of a recursive function and I don't how to do it. More precisely I want that after N recursions Python returns something like a list which contains the beginning and the end of the subset which compose the Cantor set.

도움이 되었습니까?

해결책

Here's what I came up with so you can compare your version:

def cantor(n):
    return [0.] + cant(0., 1., n) + [1.]

def cant(x, y, n):
    if n == 0:
        return []

    new_pts = [2.*x/3. + y/3., x/3. + 2.*y/3.]
    return cant(x, new_pts[0], n-1) + new_pts + cant(new_pts[1], y, n-1)

for i in range(4):
    print(i, cantor(i))

At each level of recursion, you just compute the two inner points, and patch those together with what the nested calls return.

Here's the run with recursion limits 0..3:

0 [0.0, 1.0]
1 [0.0, 0.3333333333333333, 0.6666666666666666, 1.0]
2 [0.0, 0.1111111111111111, 0.2222222222222222, 0.3333333333333333, 0.6666666666666666,0.7777777777777777, 0.8888888888888888, 1.0]
3 [0.0, 0.037037037037037035, 0.07407407407407407, 0.1111111111111111, 0.2222222222222222, 0.25925925925925924, 0.2962962962962963, 0.3333333333333333, 0.6666666666666666, 0.7037037037037037, 0.7407407407407407, 0.7777777777777777, 0.8888888888888888, 0.9259259259259258, 0.9629629629629629, 1.0]
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