WebGL: passing uniform arrays to shader

Question

Tried to do just like here: Pass array to shader And like here: Passing an array of vectors to a uniform

But still no luck. I think I do just like there but it doesn't work:

Here's my JavaScript code:

shaderProgram.lightsUniform = gl.getUniformLocation(shaderProgram, "lights"); // Getting location
gl.uniform1f(shaderProgram.lightsUniform, new Float32Array([3,1,2,3,4,5])); // Let's try to send some light (currently each light is one float) as array.

Vertex Shader Code:

uniform float lights[6]; // Declaration

...

vLight *= lights[0]; // Let's try to mutliply our light by the first array item. There should be 3.0.

Summary: I send an array to shader with non-zero-floats.

Result: totally black! I.e. lights[0] contains 0.0 but expected 3.0. If I try lights[1], lights[2] etc. they all give the same result!

Let's now try to pass just one float. I change

gl.uniform1f(shaderProgram.lightsUniform, new Float32Array([3,1,2,3,4,5])); 

to

gl.uniform1f(shaderProgram.lightsUniform, 3); // I want to send just float 3.0

Summary: instead of sending array I send just float 3.0.

Result: works! lights[0] contains 3.0 (but I sent just float, not an array).

What do I do wrong? How do I pass to shader array of uniforms?

Answer 1

Those answers all use the function uniform3fv. v as in vector.

So you should be using uniform1fv, not uniform1f for arrays of uniforms.

Answer 2

1: Make sure your if statement is within a function.

2: Make sure precision is set before declaring uniforms.

      #ifdef GL_FRAGMENT_PRECISION_HIGH
        precision highp float;
      #else
        precision mediump float;
      #endif
      precision mediump int;

3: Make sure comparison is of correct type:

This will FAIL:

uniform vec3 neon_whatever;
if(neon_whatever.x == 0){

};

This will FAIL:

uniform vec3 neon_whatever;
if(neon_whatever == 0.0){

};

This will WORK:

uniform vec3 neon_whatever;
if(neon_whatever.x == 0.0){

};