Pergunta

__builtin_expect from GCC can be used by programmer to show which variants are expected to be very often and which are rare. But __builtin_expect have only "true" and "false" (0% or 100% probability)

For some big projects it is vary hard to get profile feedback (-fprofile-arcs), and sometimes programmer does know, what probability of branch he have in some point of program.

It is possible to give a hint to compiler that a branch have probability >0% and <100% ?

Foi útil?

Solução

True and false really mean that "the first variant is more likely" and "the second variant is more likely". There's no practical need for any values other than these. The compiler won't be able to use that information.

Outras dicas

From here:

long __builtin_expect_with_probability

(long exp, long c, double probability) The function has same semantics as __builtin_expect, but caller provides the expected probability that exp == c. Last argument probability is a floating-value in the inclusive range 0.0f and 1.0f.

Non-determinism is not a desirable trait for compiler output, let alone language features. There is no real benefit to only partial optimization preferring one branch, and no compiler I'm aware of can do this.

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