Como pesquisar um padrão dentro de um arquivo e excluir as linhas em Unix na linha de comando?

StackOverflow https://stackoverflow.com/questions/1422382

  •  07-07-2019
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Pergunta

Eu preciso pesquisar um padrão em arquivos. Por exemplo, o conteúdo do arquivo está abaixo: 

3555005!K!00630000078!C!20090805235959!47001231000000!16042296!336344324!A!1!ENG!0!00630000078!NO!00630000078!
3555005!K!204042880166840!I!20090805235959!47001231000000!16042296!336344324!A!1!ENG!0!00630000078!NO!00630000078!
3555005!D!16042296!DUMMY!20090805235959!0!47001231000000!0!336344324!1!1!POST!USAGE!336344324!0!
3555005!C!336344324!1!!!EUR!1!1!!I!
3555005!S!00630000078!20090805172515!LF010300!

Aqui eu quero procurar linhas com! D! eo campo de 7º na linha é menor que a data do sistema, então eu quero excluir a linha e salve o arquivo.

É possível?

Foi útil?

Solução

Se você preferir AWK ... 

awk -f logstrip.awk  in.log > out.log

onde logstrip.awk é algo como 

# *** Simple AWK script to delete lines from log file ***
#    Rule: keep all lines except these that have their 2nd
#          field equal to "D" and their 7th field more than
#          current date time


BEGIN {
    FS = "!";   #delimiter

    stopDate = systime();
    # stopDate = 47001231000001;   for test purposes

    deletedLineCtr = 0;   #diagnostics counter, unused at this time
}

{
  if (match($2, "D") && ($7 < stopDate) ) {
    deletedLineCtr++;
  }
  else
     print $0
}

deve fazer o truque.

Atenção, no entanto, o seu campo # 7 contém um formato de data estranho. Eu acho que reconhecer um valor época recente (123 ...), mas é precedida por 4 dígitos aparentemente não relacionados. Estes podem ser facilmente removidos antes de comparar a StopDate

Outras dicas

Algo como isso deve fazer o truque ... você pode querer analisar o tempo, se isto não é como você tem o campo formatado 

perl -ne '/^([^!]+!){6}([^!]+).*/; print if $2 < time && /!D!/;'

Com base em O mjv resposta, mas simplificada e usando (assumindo), o quinto campo para a data (dividido em duas linhas para facilitar a leitura): 

awk -F! 'BEGIN {stopdate=strftime("%Y%m%d%H%M%S",systime())} 
         $2 != "D" || $5 >= stopdate {print}' file.log > newfile.log

i testado com os dados de exemplo em um arquivo 

3555005!K!00630000078!C!20090805235959!47001231000000!16042296!336344324!A!1!ENG!0!00630000078!NO!00630000078!
3555005!K!204042880166840!I!20090805235959!47001231000000!16042296!336344324!A!1!ENG!0!00630000078!NO!00630000078!
3555005!D!16042296!DUMMY!20090805235959!0!20090912000000!0!336344324!1!1!POST!vijay!336344324!0!
3555005!C!336344324!1!!!EUR!1!1!!I!
3555005!S!00630000078!20090805172515!LF010300!
3555005!K!204042880166840!I!20090805235959!47001231000000!16042296!336344324!A!1!ENG!0!00630000078!NO!00630000078!
3555005!D!16042296!DUMMY!20090805235959!0!20090912000000!0!336344324!1!1!POST!vijay!336344324!0!
3555005!C!336344324!1!!!EUR!1!1!!I!
3555005!S!00630000078!20090805172515!LF010300!
3555005!D!16042296!DUMMY!20090805235959!0!20090917000000!0!336344324!1!1!POST!USAGE!336344324!0!
3555005!C!336344324!1!!!EUR!1!1!!I!
3555005!S!00630000078!20090805172515!LF010300!
3555005!K!204042880166840!I!20090805235959!47001231000000!16042296!336344324!A!1!ENG!0!00630000078!NO!00630000078!
3555005!D!16042296!DUMMY!20090805235959!0!20090919000000!0!336344324!1!1!POST!USAGE!336344324!0!
3555005!C!336344324!1!!!EUR!1!1!!I!
3555005!S!00630000078!20090805172515!LF010300!
3555005!K!204042880166840!I!20090805235959!47001231000000!16042296!336344324!A!1!ENG!0!00630000078!NO!00630000078!
3555005!D!16042296!DUMMY!20090805235959!0!20090914000000!0!336344324!1!1!POST!vijay!336344324!0!
3555005!C!336344324!1!!!EUR!1!1!!I!
3555005!S!00630000078!20090805172515!LF010300!
3555005!K!204042880166840!I!20090805235959!47001231000000!16042296!336344324!A!1!ENG!0!00630000078!NO!00630000078!
3555005!D!16042296!DUMMY!20090805235959!0!20090915000000!0!336344324!1!1!POST!vijay!336344324!0!
3555005!C!336344324!1!!!EUR!1!1!!I!
3555005!S!00630000078!20090805172515!LF010300!
3555005!K!204042880166840!I!20090805235959!47001231000000!16042296!336344324!A!1!ENG!0!00630000078!NO!00630000078!
3555005!D!16042296!DUMMY!20090805235959!0!20090913000000!0!336344324!1!1!POST!vijay!336344324!0!
3555005!C!336344324!1!!!EUR!1!1!!I!
3555005!S!00630000078!20090805172515!LF010300!
3555005!K!204042880166840!I!20090805235959!47001231000000!16042296!336344324!A!1!ENG!0!00630000078!NO!00630000078!
3555005!D!16042296!DUMMY!20090805235959!0!20090912000000!0!336344324!1!1!POST!USAGE!336344324!0!
3555005!C!336344324!1!!!EUR!1!1!!I!
3555005!S!00630000078!20090805172515!LF010300!
3555005!K!204042880166840!I!20090805235959!47001231000000!16042296!336344324!A!1!ENG!0!00630000078!NO!00630000078!
3555005!D!16042296!DUMMY!20090805235959!0!20090912000000!0!336344324!1!1!POST!USAGE!336344324!0!

mas é está excluindo todas as linhas que consiste em! D !. Eu usei o seguinte script awk 

# *** Simple AWK script to delete lines from log file ***
#    Rule: keep all lines except these that have their 2nd
#    field equal to "D" and their 7th field more than
#          current date time
BEGIN {
       FS = "!";
         #delimiter
         stopDate = "date +%Y%m%d%H%M%S";
         # stopDate = 47001231000001;  for test purposes
         deletedLineCtr = 0;   #diagnostics counter, unused at this time
      }
      {
      if ( match($2, "D") && ($7 < stopDate) )
          {
           deletedLineCtr++;
          }
      else
           print $0
      }

Estou fazendo algo errado?

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