Simply use std::ref
in C++11 or boost::ref
when not having access to C++11.
How do I stop std/boost::thread copying my object rather than passing references?
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05-08-2022 - |
Pergunta
From the output of this sample project I am seeing three copies of my object created when I'd expect only one. And want only one. How should I fix this?
In my real code ThreadedThing is a significantly larger/heavier class that sits in a threadpool and I'd rather have only as many of them as I really need. But I've written a little demo app (below) that demonstrates the behaviour. I copied the basic code from a boost threading sample so I expected it to work properly, so I fear this is a C++ novice question.
I've written multithreaded code before, but in Delphi rather than C++. For this code valgrind says there's no leaks, which is all very well but there are still three objects created where I would rather have one.
#include <iostream>
#include <boost/thread.hpp>
using namespace std;
class ThreadedThing {
public:
ThreadedThing() {
cout << "ThreadedThing created" << endl;
}
ThreadedThing(const ThreadedThing &orig) {
cout << "ThreadedThing copy created" << endl;
}
~ThreadedThing() {
cout << "ThreadedThing destroyed" << endl;
}
void operator()() {
cout << "ThreadedThing running" << endl;
sleep(2);
}
};
int main() {
std::vector < shared_ptr < boost::thread >> threads;
cout << "Started" << endl;
ThreadedThing thing;
std::shared_ptr<boost::thread> thread(new boost::thread(thing));
threads.push_back(thread);
for (std::vector < std::shared_ptr < boost::thread >> ::iterator it = threads.begin(); it != threads.end(); ++it) {
(*it)->join();
cout << "joined" << endl;
}
cout << "stopped" << endl;
return 0;
}
/* output
Started
ThreadedThing created
ThreadedThing copy created
ThreadedThing copy created
ThreadedThing destroyed
ThreadedThing running
ThreadedThing destroyed
joined
stopped
ThreadedThing destroyed
*/
Solução
Outras dicas
It is well documented that the constructor of boost::thread
, same with std::thread
, does not accept references as argument. To overcome this problem, you can write a little shell object that encompasses the reference and keeps it even when copied.
This is how I did it:
/* container to allow passing an object reference to std::thread()
* without this std::thread() would run on a copy
*/
template<typename T>
struct holder {
holder(T& payload) : payload(payload) {}
void operator()() { payload(); }
T& payload;
};
Then use it like this:
BackgroundTaskQueue queue;
// start worker thread
holder<BackgroundTaskQueue> h(queue);
queuethread = new std::thread(h);
// h is not needed anymore