The format of this is quite crazy. Unfortunately this means you will need to parse the xml manually with XDocument
or XmlDocument
. Lets use the former as it is easier:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Xml.Linq;
namespace Xmlarrayload
{
class Program
{
static void Main(string[] args)
{
var document = XDocument.Parse(@"<TIMEWINDOWS>
<NUMBER>4</NUMBER>
<NO0>
<FROM>22-11-2013 08:00:00</FROM>
<TO>22-11-2013 11:59:00</TO>
</NO0>
<NO1>
<FROM>22-11-2013 12:00:00</FROM>
<TO>22-11-2013 15:59:00</TO>
</NO1>
<NO2>
<FROM>23-11-2013 08:00:00</FROM>
<TO>23-11-2013 11:59:00</TO>
</NO2>
<NO3>
<FROM>23-11-2013 12:00:00</FROM>
<TO>23-11-2013 15:59:00</TO>
</NO3>
</TIMEWINDOWS>");
int number = int.Parse(document.Root.Element("NUMBER").Value);
TimeWindow[] windows = (TimeWindow[])Array.CreateInstance(typeof(TimeWindow), number);
for (int i = 0; i < number; i++)
{
var element = document.Root.Element(string.Format("NO{0}", i));
TimeWindow window = new TimeWindow
{
//it is extremely important to use the correct culture (invariant) to parse the dates.
To = DateTime.ParseExact(element.Element("TO").Value, "dd-MM-yyyy HH:mm:ss", System.Globalization.CultureInfo.InvariantCulture.DateTimeFormat),
From = DateTime.ParseExact(element.Element("FROM").Value, "dd-MM-yyyy HH:mm:ss", System.Globalization.CultureInfo.InvariantCulture.DateTimeFormat)
};
windows[i] = window;
}
}
}
public class TimeWindow
{
public DateTime From { get; set; }
public DateTime To { get; set; }
}
}