Just convert each item to string
.
print ",".join(str(i) for i in table1)
If you want to keep the unicode
items as is, then :
print ",".join(str(i) if not isinstance(i, unicode) else i for i in table1)
Pergunta
Hi i'm using the python and odbc database i.e Microsoft access. I'm getting the output like
(u'EXPANDx TB', 12.0, 10.0, 11.0, 13.0, 0.0, 46.0)
(u'EXPANDx TB & GFATM', 1.0, 1.0, 0.0, 1.0, 0.0, 3.0)
(u'EXPANDx TB & NRHM', 0.0, 0.0, 1.0, 0.0, 0.0, 1.0)
(u'GFATM', 1.0, 1.0, 0.0, 0.0, 0.0, 2.0)
(u'WHO', 3.0, 7.0, 3.0, 5.0, 0.0, 18.0)
(u'GFATM & EXPANDx TB', 1.0, 0.0, 0.0, 0.0, 0.0, 1.0)
the extra term "u" is displaying. I also used the join function but getting the error like
print ",".join(table1)
TypeError: sequence item 1: expected string or Unicode, float found
please help me out with this. Thanks in advance.
#!/usr/bin/python
import pyodbc
db_file = r'''C:\Users\Basavaraj\Documents\C&DST.accdb'''
user = ''
password = ''
odbc_conn_str = 'DRIVER={Microsoft Access Driver (*.mdb, *.accdb)};DBQ=%s;UID=%s;PWD=%s' % \
(db_file, user, password)
conn= pyodbc.connect(odbc_conn_str)
#for row in cursor.fetchall():
# print row[2]
try:
cursor = conn.cursor()
cursor.execute("select * from Table1")
for table1 in cursor.fetchall():
print ",".join(table1)
finally:
conn.close()
`
Solução
Just convert each item to string
.
print ",".join(str(i) for i in table1)
If you want to keep the unicode
items as is, then :
print ",".join(str(i) if not isinstance(i, unicode) else i for i in table1)