Pergunta

I have a simple code that gives a JSON response for a specific route. Here's my current code:

var express = require('express')
  , async = require('async')
  , http = require('http')
  , mysql = require('mysql');

var app = express();

var connection = mysql.createConnection({
    host: 'localhost',
    user: '****',
    password: "****",
    database: 'restaurants'
});

connection.connect();

// all environments
app.set('port', process.env.PORT || 1235);
app.use(express.static(__dirname + '/public/images'));


app.get('/DescriptionSortedRating/',function(request,response){
    var name_of_restaurants;

    async.series( [
        // Get the first table contents
        function ( callback ) {
            connection.query('SELECT * FROM restaurants ORDER BY restaurantRATING', function(err, rows, fields)
                {
                        console.log('Connection result error '+err);
                        name_of_restaurants = rows;
                        callback();
                });

 }
   // Send the response
], function ( error, results ) {
    response.json({
        'restaurants' : name_of_restaurants
    });
} );

} );



http.createServer(app).listen(app.get('port'), function(){
  console.log('Express server listening on port ' + app.get('port'));
});

How can I make an XML response equivalent to the JSON above?

Foi útil?

Solução

You can use any number of the XML libraries available on npm. Here's an example using the simply-named "xml" library:

var xml = require('xml');

response.set('Content-Type', 'text/xml');
response.send(xml(name_of_restaurants));

See the module's documentation for a description of how it converts JavaScript objects to XML. If you need things returned in a specific XML format, you'll have more work to do, of course.

Outras dicas

As an update to this, it looks like res.type should be used instead as res.set does not give the same results.

res.type('application/xml');

More information can be found in the API reference.

Licenciado em: CC-BY-SA com atribuição
Não afiliado a StackOverflow
scroll top