Using Jquery.attr() to Get DIV IDs

StackOverflow https://stackoverflow.com/questions/7812608

  •  26-10-2019
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Pergunta

I want to use the .each and .attr function to get div ids. I know how to do that, but what I want to do is grab each div ID from the DOM with a certain class (let's say "edit" class) and .append some data into that div.

Here's what I am having trouble with: I want to put the ID of that particular DIV in the .each loop inside the .append. For example: if I wanted to put a link inside the .append, I would want the link to be http://www.website.com/index.php?id=1&div=DIV-ID

Any ideas, and I'm sorta a novice, so can you provide code example. I understand attr and .each though to an extent.

Foi útil?

Solução

http://jsfiddle.net/WrGLC/1/

For the sake of keeping it on this page:

HTML:

<div id="1" class="edit">A</div>
<div id="2" class="edit">B</div>
<div id="3">C</div>

JS:

// Anonymous loop, in case you copy and paste this script, the vars won't get confused
(function() {

    // Loop for each .edit
    $('.edit').each(function() {

        // Update the text inside
        $(this).html('http://www.website.com/id='+$(this).attr('id'));

    });

})();

Outras dicas

Here's an untested solution that looks like it should work. It may not work if there are multiple classes assigned to the div elements.

$(function() {
    $('div').each(function() {
        var _t = $(this);
        var id = _t.attr("id");
        if(_t.attr("class") == "someClass") {
            _t.append("<a href = 'http://www.website.com/index.php?id=1&div="+id+"'>Hello World!</a>");

        }
    });
});

I'll guess. You want this?

$( '.edit' ).append( function () {
    return '<a href="http://www.website.com/index.php?id=1&div=' + 
        this.id + '">link</a>';
});

I think I'm correctly interpreting your conditions:

<!DOCTYPE html>
<html lang="en">
    <head>
        <meta charset="utf-8"/>
    </head>
    <body>
        <div id="a" class="edit">A</div>
        <div id="b" class="edit">B</div>
        <div id="c">C</div>
        <div id="d" class="save">D</div>
        <div id="e" class="edit">E</div>
        <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"></script>
        <script type="text/javascript">
            (function ($) {
                $("div.edit").each(function (i) {
                    var $div = $(this);
                    $div.append('<a href="http://www.website.com/index.php?id=1&div=' + $div.attr("id") + '">Link</a>');
                });
            })(jQuery);
        </script>
    </body>
</html>

UPDATE: @JohnHartsock is correct. No each method is needed here. I'd adjust my code as follows:

<!DOCTYPE html>
<html lang="en">
    <head>
        <meta charset="utf-8"/>
    </head>
    <body>
        <div id="a" class="edit">A</div>
        <div id="b" class="edit">B</div>
        <div id="c">C</div>
        <div id="d" class="save">D</div>
        <div id="e" class="edit">E</div>
        <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"></script>
        <script type="text/javascript">
            (function ($) {
                $("div.edit").append(function () {
                    var $div = $(this);
                    $div.append('<a href="http://www.website.com/index.php?id=1&div=' + $div.attr("id") + '">Link</a>');
                });
            })(jQuery);
        </script>
    </body>
</html>

I don't believe an jQuery call to each() would be necessary. With append() you can pass a function where this will represent the current iteration of your selector.

$('div.mydivclass').append(function () {
  return '<a href="http://www.website.com/index.php?id=1&div='+ this.id + '">My Div link</a>';
});

Here is a fiddle http://jsfiddle.net/WFd7k/

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