counting the occurrences of a field on a individual line

Question

I am trying to take a file that has many 1000's of lines, and for each lines I would like to count the occurrences that the individuals fields occur. So an example of a few lines of the file look like this:

0/0     0/0     0/0     0/0     0/0     0/0     0/1     0/0     0/0     1/1     0/0     0/1
0/1     1/1     0/1     0/0     0/0     0/0     0/0     0/0     0/0     0/0     0/0     0/0

my code is this:

cat file | awk 'BEGIN{a=0; c=0; g=0;} {a+=gsub("0/0",""); c+=gsub("0/1",""); g+=gsub("1/1","")} END{print a,c,g}'

The output that I get is:
18 4 2

The output that I want is:

    line #1- 9 2 1
    line #2- 9 2 1

I can't seem to figure out what I am doing wrong

Answer 1

awk '{print "line #", NR, "-", gsub("0/0",""), gsub("0/1",""), gsub("1/1","")}' file

Answer 2

With GNU awk you can try something like this (The output can be random. Since you haven't mentioned the order you'd like to get, I am assuming this should be ok):

awk '{delete a; printf "line #%s- ", NR; for(x=1;x<=NF;x++) a[$x]++; for(y in a) printf "%s ", a[y]; print ""}' file

Output:

$ cat file
0/0     0/0     0/0     0/0     0/0     0/0     0/1     0/0     0/0     1/1     0/0     0/1
0/1     1/1     0/1     0/0     0/0     0/0     0/0     0/0     0/0     0/0     0/0     0/0
$ awk '{delete a; printf "line #%s- ", NR; for(x=1;x<=NF;x++) a[$x]++; for(y in a) printf "%s ", a[y]; print ""}' file
line #1- 9 2 1 
line #2- 9 2 1