Put the bytes into a buffer and ask C
to interpret the memory as a double.
#include <stdio.h>
int main(){
char* foo = "\x00\x00\x00\x00\x00\x00\x24\x40";
double bar =*((double*) foo);
printf("%f\n", bar);
}
Output:
10.000000
Pergunta
So basically I disassemble some code on 32bit Linux and in the rodata section, where double should exist, I find these 8 bytes:
00000000 00002440
The original double number is 10.0
Could anyone tell me how to transform this 8 bytes into double?
Solução
Put the bytes into a buffer and ask C
to interpret the memory as a double.
#include <stdio.h>
int main(){
char* foo = "\x00\x00\x00\x00\x00\x00\x24\x40";
double bar =*((double*) foo);
printf("%f\n", bar);
}
Output:
10.000000