No, the doneCallback
happens before the return
, because the result of the doneCallback
is the function's return value. doneCallback
will be called once for each time that square
is invoked.
async js with node
-
11-07-2023 - |
Pergunta
What is the progression of this function using the async.js library?
var async = require('async');
var square = function (num, doneCallback) {
console.log(num * num);
// Nothing went wrong, so callback with a null error.
return doneCallback(null);
};
// Square each number in the array [1, 2, 3, 4]
async.each([1, 2, 3, 4], square, function (err) {
// Square has been called on each of the numbers
// so we're now done!
console.log("Finished!");
});
In the 'square' function, is the return doneCallback(null) ran every time a new number is passed, or is it ran after all the numbers are finished?
I think it is ran after all the numbers have been passed and console.log'd, IMO the return would interrupt and stop the function. Is this what is actually happening?
Solução
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