Bash echo status

Question

I'm trying to create a bash script which will display the statuses of multiple services. The function I created to display the status is as follows:

printStatus() {
  if checkProcess "${1}"; then
    echo -e "${1} status: \t\t [RUNNING]"
  else
    echo -e "${1} status: \t\t [DOWN]"
  fi
}

The problem is that $1 has a variable size, which for example, creates the following result:

Mysql status:        [RUNNING]
PHP-fpm status:          [RUNNING]

How can I manage to get the [RUNNING] tags perfectly underneath each other? So I'd like to have it as follows:

Mysql status:            [RUNNING]
PHP-fpm status:          [RUNNING]

EDIT - SOLVED

This is my function after Mat's answer:

printStatus() {
  if checkProcess "${1}"; then
    printf "%-30s%s" "${1} status:"  "[RUNNING]"
  else
    printf "%-30s%s" "${1} status:" "[DOWN]"
  fi
  echo # <-- I know, being lazy here for the new line...
}

Answer 1

Use printf instead of echo for this sort of thing. Something like:

printf "%-30s%s" "left justified text" "[status]"

If your process name is longer than whatever length you chose though, they'll miss-align (i.e. printf won't truncate).

Answer 2

Use printf instead of echo. Example:

printf "%-16s%s" "${1}" "[RUNNING]"

You'll have to adjust the length of the formating to your max expected value.