Pergunta

nt main()
{
    cout << ('a'^'b');
}

when i wrote this simple code(in C++) program giving the "3" output. but it must be "1". do you know why? is there problem with the xor operator??

Foi útil?

Solução

There is no problem with XOR and the result of 3 is correct.

   'a' XOR 'b'
-> 0x61 XOR 0x62          (hex, per ASCII)
-> 01100001 XOR 01100010  (binary)
-> 00000011               (only these bits differ)
-> 3                      (decimal)

Consider the following, which is 1 - why?

'`' ^ 'a'
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