Pergunta

Let's say we have number 4920 and we want to find the closest $n^x$ to 4920

2 ^ 12 = 4096 but it's not the closest possible $n^x$, for example 17 ^ 3 = 4913 is closer to 4920

The question is, how do we find the closest $n^x$, where $n$ and $x$ are less than 2 digits long? (because $4913^1$ is not what I want)

Nenhuma solução correta

Licenciado em: CC-BY-SA com atribuição
Não afiliado a cs.stackexchange
scroll top