Pergunta

I try to implement my own example based on official tutorial Sparklr2/Tonr2. Everything looks good but when I remove from web.xml in my Tonr2 implementation, spring security filter I have exception:

No redirect URI has been established for the current request

I can't understand what URL should I use. Here is my code, for client implementation:

<!--apply the oauth client context -->
<oauth:client id="oauth2ClientFilter" />

<!--define an oauth 2 resource for sparklr -->
<oauth:resource id="provider" type="authorization_code" client-id="client" client-secret="secret" 
    access-token-uri="http://localhost:8080/provider/oauth/token" user-authorization-uri="http://localhost:8080/provider/oauth/authorize" scope="read,write" />

<beans:bean id="clientController" class="com.aouth.client.ClientController">
    <beans:property name="trustedClientRestTemplate">
        <oauth:rest-template resource="provider" />
    </beans:property>
</beans:bean>

And for provider:

<http pattern="/oauth/token" create-session="stateless" authentication-manager-ref="clientAuthenticationManager" xmlns="http://www.springframework.org/schema/security">
    <intercept-url pattern="/oauth/token" access="IS_AUTHENTICATED_FULLY" />
    <anonymous enabled="false" />
    <http-basic />
</http>

<authentication-manager id="clientAuthenticationManager" xmlns="http://www.springframework.org/schema/security">
    <authentication-provider user-service-ref="clientDetailsUserService" />
</authentication-manager>

<bean id="clientDetailsUserService" class="org.springframework.security.oauth2.provider.client.ClientDetailsUserDetailsService">
    <constructor-arg ref="clientDetails" />
</bean>

<!-- The OAuth2 protected resources are separated out into their own block so we can deal with authorization and error handling 
    separately. This isn't mandatory, but it makes it easier to control the behaviour. -->
<http pattern="/secured" create-session="never" access-decision-manager-ref="accessDecisionManager" xmlns="http://www.springframework.org/schema/security">
    <anonymous enabled="false" />
    <intercept-url pattern="/secured" access="ROLE_USER,SCOPE_READ" />
    <custom-filter ref="resourceServerFilter" before="PRE_AUTH_FILTER" />
    <http-basic />
</http>

<bean id="accessDecisionManager" class="org.springframework.security.access.vote.UnanimousBased" xmlns="http://www.springframework.org/schema/beans">
    <constructor-arg>
        <list>
            <bean class="org.springframework.security.oauth2.provider.vote.ScopeVoter" />
            <bean class="org.springframework.security.access.vote.RoleVoter" />
            <bean class="org.springframework.security.access.vote.AuthenticatedVoter" />
        </list>
    </constructor-arg>
</bean>

<oauth:resource-server id="resourceServerFilter" resource-id="resource" token-services-ref="tokenServices" />

<bean id="tokenServices" class="org.springframework.security.oauth2.provider.token.DefaultTokenServices">
    <property name="tokenStore" ref="tokenStore" />
    <property name="supportRefreshToken" value="true" />
    <property name="clientDetailsService" ref="clientDetails"/>
</bean>

<bean id="tokenStore" class="org.springframework.security.oauth2.provider.token.InMemoryTokenStore" />

<http auto-config="true" xmlns="http://www.springframework.org/schema/security">
    <intercept-url pattern="/test" access="ROLE_USER" />
    <intercept-url pattern="/" access="IS_AUTHENTICATED_ANONYMOUSLY" />
</http>

<authentication-manager alias="authenticationManager" xmlns="http://www.springframework.org/schema/security">
    <authentication-provider>
        <user-service>
            <user name="pr" password="pr" authorities="ROLE_USER" />
        </user-service>
    </authentication-provider>
</authentication-manager>

<oauth:authorization-server client-details-service-ref="clientDetails" token-services-ref="tokenServices" >
    <oauth:authorization-code />
    <oauth:implicit />
    <oauth:refresh-token />
    <oauth:client-credentials />
    <oauth:password />
</oauth:authorization-server>

<oauth:client-details-service id="clientDetails">
    <oauth:client client-id="client" resource-ids="resource" authorized-grant-types="authorization_code, implicit"
        authorities="ROLE_CLIENT" scope="read,write" secret="secret" />
</oauth:client-details-service>

I just want my client to work without spring security. And when I need my protected resource I want to login only on provider side.

Foi útil?

Solução

You 2nd XML that you pasted here is the spring's XML for the oauth-provider and the protected-resource, which in your case run in the same webapp. (you can separate them, of course, if you wish).

The client (the 1st pasted-XML) is a different story. If I understand you correctly, you want your client to run without Spring's help (to be a regular webapp, and not spring-security-oauth-client webapp).

You have to understand how oAuth works: the client tries to get to a protected resource; if it does not have the access-token, it is being redirected to the oAuth-provider (that shows the login page and supplies the token). By the standard, the request for the access-token MUST contain a "redirect-uri" param, so after a successful login, the oAuth-provider knows where to redirect the client to. The oAuth client does it for you, and if you delete the "oauth client" from your web.xml, you now have to implement this by yourself.

Thanks for your answer. But I still don't understand how spring security influences my oAuth client. And can I use for client side spring-oauth (spring-mvc) without spring-security?

When you write this line in your XML:

< oauth:client id="oauth2ClientFilter" />

it means that you use spring-security-oauth, which is a package dedicated for oauth, built on spring-security. If you dig in, it puts a special filter (OAuth2ClientContextFilter) in the chain that handles the oAuth stuff, that are relevant for the client. One of them is sending the request with all the params ("redirect-uri" is one of them).

If you decide NOT to use spring-security-oauth, well - you will have to implement this logic by yourself...

Hope that helps!

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