Is is possible for my Waf wscript to call other wscripts in the current directory?

Question

I am building a project with Waf. It has several third-party dependencies, and I would like to build each dependency from my main wscript. My project is organized like this:

/boost/
/gtest/
/source/
/waf
/wscript
/wscript_boost
/wscript_gtest

Each "dependency" wscript_* has commands defined, just like my main wscript.

def options(opt): pass
def configure(conf): pass
def build(bld): pass

If I had put the dependency wscript files in the dependency folders, I could just call opt.recurse('boost gtest'), but I don't want to mix my files with third-party files.

Is there any way for my wscript to call into wscript_boost and wscript_gtest?

Answer 1

I don't think it is possible in the current Waf implementation (waflib.Context.Context.recurse uses a global WSCRIPT_FILE variable).

Though ugly, it is possible to hack this at the beginning of your main wscript:

import waflib.Context
original_recurse = waflib.Context.Context.recurse

def new_recurse(ctx,*args, **kwargs):
  original_wscript_file = waflib.Context.WSCRIPT_FILE
  try:
    waflib.Context.WSCRIPT_FILE = (original_wscript_file + 
                                   kwargs.pop('suffix', ''))

    original_recurse(ctx, *args, **kwargs)
  finally:
    waflib.Context.WSCRIPT_FILE = original_wscript_file

waflib.Context.Context.recurse = new_recurse

Your main wscript would the be something like:

def configure(cfg):
  cfg.recurse(suffix='_boost')
  cfg.recurse(suffix='_gtest')

Note that there are some side effects, as WSCRIPT_FILE is suffixed when you are inside the wscript_boost file.

You can also submit an issue to the waf project.

Answer 2

The way to do that is usually to put a wscript into each subdirectory and to use recurse :

/boost/
/boost/wscript
/gtest/wscript
/source/
/waf
/wscript

And use recurse :

def build(bld):
     # ...
     bld.recurse("boost")
     bld.recurse("gtest")
     # ...