Does this work?
gsub("A/V","A/B",x$question)
Example:
x<-c("A/V", "A/V", "A/V")
x<-gsub("A/V","A/B",x)
>x
[1] "A/B" "A/B" "A/B"
Note: You can use ifelse
for that too.
> ifelse(x=="A/B","A/V",x)
[1] "A/V" "A/V" "A/V"
Pergunta
after a lot of trial/error and the search function I am still somewhat clueless about an I-thought-simple-thing (as always, hrmpf):
I have a column in a data frame x$question
and within that column, there is an expression 'A/V'
every once in a while, and I simply want it to be changed to 'A / B'
.
I tried a little here and there, and thought this should work:
x$question[agrep('A/V',x$question)]<-'A / B'
but I get the error:
In `[<-.factor`(`*tmp*`, agrep('A/V', :
invalid factor level, NAs generated
or I could do this
agrep('A/V','A / B', x$question).
But here I get the error:
Error in .amatch_bounds(max.distance) :
match distance components must be non-negative
Since I am quite out of ideas, I would be very thankful, if you had a suggestions, or maybe an even simpler way of replacing a string with another string.
Solução
Does this work?
gsub("A/V","A/B",x$question)
Example:
x<-c("A/V", "A/V", "A/V")
x<-gsub("A/V","A/B",x)
>x
[1] "A/B" "A/B" "A/B"
Note: You can use ifelse
for that too.
> ifelse(x=="A/B","A/V",x)
[1] "A/V" "A/V" "A/V"