subtraction of a minimum value within an array in a list

Question

Suppose I have a list

x = [[1,2,3],[5,4,20],[9,100,7]]

I want to something similar to:

xcor = x - min(x) #should return [[0,1,2],[1,0,16],[2,93,0]]

Answer 1

[[y-m for y in q] for (q,m) in [[q,min(q)] for q in x]]

Answer 2

Well try exactly what you say.

Find the minimum value first and either edit the existing list or create a new array.

Something like this for the minimum:

def min_value(x):
    min = x[0]
    for i in range(len(x)):
        if x[i] < min:
            min = cell
    return min

and either something this

def subtract_min_from_each_list(x):
    for i in range(len(x)):
        min = min_value(x[i])
        for j in range(len(x[i])):
            x[i][j] = x[i][j] - min
    return x

or this

def get_subtracted_list(x):
    new_x = []
    for i in range(len(x)):
        temp = []
        min = min_value(x[i])
        for j in range(len(x[i])):
            temp.append(x[i][j] - min)
        new_x.append(temp)
    return new_x

to act on your list.

Answer 3

you can try following in python

x = [[1,2,3], [5,4,20], [9,100,7]]

for n in range(len(x)):
    pivot = x[n][n]
    for m in range(len(x[0])):
        x[n][m] = x[n][m] - pivot

print x