Вопрос

I want to call a c function from python using ctypes. From the documentation I don't understand how to pass pointer to vectors. The function I want to call is:

double f(int n, double* x)
  {
    int i;
    double p=1;
    for (i=0; i< n; i ++) 
      p = p * x[i];
    return p;
  }

I have modified the function with void pointer, so it becomes f(int, void*) with an internal cast to double. I do the following:

def f(x):
  n = len(x)
  libc = '/path/to/lib.so'
  cn = c_int(n)
  px = pointer(x)
  cx = c_void_p(px)
  libc.restype = c_double
  L = libc.f(cn, cx)
  return L

I assume that x is a numpy array, but I am not sure how the numpy array are organized in the memory and if this is the best solution.


Edit:

None of the proposed methods work with my numpy array, maybe it is due to how I am defining the array:

x = np.array([], 'float64')
f = open(file,'r')
for line in f:
  x = np.append(x,float(line))

but some of them work if I have an explicit list like [1,2,3,4,5], rather than a list that has been defined somewhere else and it is referred as x

Это было полезно?

Решение

Based on @Sven Marnach's answer:

#!/usr/bin/env python
import ctypes
import numpy as np
from numpy.ctypeslib import ndpointer

libf = ctypes.cdll.LoadLibrary('/path/to/lib.so')
libf.f.restype = ctypes.c_double
libf.f.argtypes = [ctypes.c_int, ndpointer(ctypes.c_double)]

def f(a):
    return libf.f(a.size, np.ascontiguousarray(a, np.float64))

if __name__=="__main__":
    # slice to create non-contiguous array
    a = np.arange(1, 7, dtype=np.float64)[::2]
    assert not a.flags['C_CONTIGUOUS']
    print(a)
    print(np.multiply.reduce(a))
    print(f(a))

Output

[ 1.  3.  5.]
15.0
15.0

Removing np.ascontiguousarray() call produces the wrong result (6.0 on my machine).

Другие советы

You can call it like this:

#!python
from ctypes import *

#!python
from ctypes import *

# double f(int n, double* x)
f = CDLL('/path/to/lib.so').f
f.argtypes = [c_int, POINTER(c_double)]
f.restype = c_double

if __name__ == '__main__':
    array = (c_double * 5)(1, 2, 3, 4, 5)
    r = f(len(array), array)
    print(r)

If you have numpy array, you can use numpy.array.ctypes.data_as:

#!python
from ctypes import *
import numpy

# double f(int n, double* x)
f = CDLL('/path/to/lib.so').f
f.argtypes = [c_int, POINTER(c_double)]
f.restype = c_double

if __name__ == '__main__':
    array = numpy.array([1, 2, 3, 4, 5])
    r = f(array.size, array.astype(numpy.double).ctypes.data_as(POINTER(c_double)))
    print(r)

or:

#!python
from ctypes import *
import numpy

# double f(int n, double* x)
f = CDLL('/path/to/lib.so').f
f.argtypes = [c_int, POINTER(c_double)]
f.restype = c_double

if __name__ == '__main__':
    array = numpy.double([1, 2, 3, 4, 5])
    r = f(array.size, array.ctypes.data_as(POINTER(c_double)))
    print(r)

apparently I needed to specify the flag contigous to make it work

http://scipy-lectures.github.io/advanced/interfacing_with_c/interfacing_with_c.html

this is an extract from my code:

array_1d_double = numpy.ctypeslib.ndpointer(dtype=numpy.double, ndim=1, 
                                            flags='CONTIGUOUS')
libc.f.argtypes = [c_int, array_1d_double]
libc.f(n, x)
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