Вопрос

HierCluster is the list of data frames.

I can get the info about one cluster like this:

tail(sort(colMeans(HierCluster[[i]])))

where i is an i-th element in the list.

I used lapply to get the info on all the clusters at once:

lapply(lapply(lapply(HierCluster, colMeans), sort), tail)

But using lapply 3 times seems rather cumbersome, is there a more practical way of doing this?

Это было полезно?

Решение

You can make an anonymous function that combines the three:

lapply(HierCluster, function(x) tail(sort(colMeans(x))))
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