Correct prototype chain in console (with object inheritance)

Question

Forgive me for being bothered by something that works, yet not showing up 'as expected' on the console.

Consider the following code:

function Person() {};
Person.prototype.PersonAction = function() {}

console.log( new Person() );

The console will show:

Person {PersonAction: function}
    __proto__: Person
        PersonAction: function () {}
        constructor: function Person() {}
        __proto__: Object

That's all good. Now consider this code:

function Mammal() {};
Mammal.prototype.MammalAction = function() {}

function Person() {};
Person.prototype = new Mammal();
Person.prototype.PersonAction = function() {}

console.log( new Person() );

The console will show:

Person {PersonAction: function, MammalAction: function}
    __proto__: Mammal
        PersonAction: function () {}
        __proto__: Mammal
            MammalAction: function () {}
            constructor: function Mammal() {}
            __proto__: Object

While this works (and I understand why it shows up this way), notice two prototypes of Mammal, with the top one having PersonAction. That's the bit I'm bothered by.

I wonder if there is any way to get this right, by 'right' I assume:

Person {PersonAction: function}
    __proto__: Person
        PersonAction: function () {}
        constructor: function Person() {}
        __proto__: Mammal
            MammalAction: function () {}
            constructor: function Mammal() {}
            __proto__: Object

Answer 1

This will do it by setting the constructor back to what it's supposed to be and using Object.create() for the prototype:

function Mammal() {};
Mammal.prototype.MammalAction = function() {}

function Person() {};
Person.prototype = Object.create(Mammal.prototype);
Person.prototype.PersonAction = function() {}
Person.prototype.constructor = Person;

console.log( new Person() );

It gives you this in Chrome:

Person {PersonAction: function, constructor: function, MammalAction: function}
    __proto__: Person
        PersonAction: function () {}
        constructor: function Person() {}
       __proto__: Mammal
           MammalAction: function () {}
           constructor: function Mammal() {}
           __proto__: Object

Demo: http://jsfiddle.net/jfriend00/CJF3L/

Answer 2

It is correct, you set Person prototype with an instance of mammal and added a property personaction.

I assume personaction is not a constructor so it should not be capitalizes, its better to use object.create instead of creating an instance of parent to set the prototype part of inheritance.

More info here: Prototypical inheritance - writing up