working with smarty and mysql database?

StackOverflow https://stackoverflow.com/questions/23343850

  •  11-07-2023
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Вопрос

this is the first time that I need to work with smarty and it seems quite straight forward.

however, there is twist in my PHP code and that is causing an issue.

here is what I am trying to do:

Before you start beating me for not using mysqli functions etc, please note that this code is just a simple test for me to understand the smarty first. so i won't be using mysql in my project and I do not recommend anyone to do so...

any way, here is what I am trying to do:

I am using the following code in my index.php page:

<?php
header("Content-type: text/html; charset=utf-8");
function isSubdomain()
{
    $host = $_SERVER['HTTP_HOST'];
    $host = explode('.',$host);
    $host = (is_array($host)?$host[0]:$host);
    return $host;
}
?>
<?php
// These are the smarty files
require 'libs/Smarty.class.php';

// This is a file which abstracts the DB connecting functionality (Check out PEAR)
include "config/connect_to_mysql.php";

$smarty = new Smarty;

$smarty->compile_check = true;
$smarty->debugging = false;
$smarty->use_sub_dirs = false;
$smarty->caching = true;

// This SQL statement will get the 5 most recently added new items from the database

$storeShop = isSubdomain();
echo $storeShop;

$sql = 'SELECT * ';
$sql .= 'FROM $storeShop ';
$sql .= 'ORDER BY `id` ';

$result = mysql_query($sql) or die("Query failed : " . mysql_error());

// For each result that we got from the Database
while ($line = mysql_fetch_assoc($result))
{
 $value[] = $line;
}

// Assign this array to smarty...
$smarty->assign('storeShop', $value);



// Assign this array to smarty...
$smarty->assign('$storeShop', $value);

// Display the news page through the news template
$smarty->display('index.tpl');

// Thanks to David C James for a code improvement :)
?>

and this is the index.tpl file:

<!-- This is the DOC type declaration and links in the CSS stylesheet etc -->
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
  <head>
    <meta http-equiv="content-type" content="application/xhtml+xml; charset=utf-8" />
    <meta name="author" content="Steve Rendell" />
    <meta name="generator" content="EditPlus" />
    <link rel="stylesheet" type="text/css" href="style.css" title="Default CSS Sheet" />

    <title>News Page</title>
  </head>

  <body id="top">

    <!-- OK display the page header to keep it nice-->
    <div id="header">
      <span>Steve's News Page</span>
    </div>

    <!-- This is where the news article will be going -->
    <div id="bodyText">

        <!-- Have a title -->
        <h1 id="welcome">Read All About It</h1>

        <!-- OK this is a section which will loop round for every item in $news (passed in through from PHP) -->
{section name=storeShop loop=$storeShop}
   <!-- For every item, display the Title -->
  <h2 id="{$storeShop[$storeShop].id}">{$storeShop[storeShop].product_name}</h2>
  <!-- Write out the Author information and the date -->
  <h3>{$storeShop[storeShop].price}, {$storeShop[storeShop].details}</h3>
  <!-- Now show the news article -->
  {$storeShop[storeShop].details}
{/section}
    </div>

    <!-- Show copyright information etc -->
    <div id="footer">All Contents Copy Written :)</div>

  <!-- Close the html tags -->
  </body>
</html>

when I run the index.php in my browser, I get the following error:

Query failed : Table 'mrshoppc_mainly.$storeShop' doesn't exist

But when I use the following code, I get the right output which is the name of the subdomain and the name of the table in mysql database as well:

$storeShop = isSubdomain();
echo $storeShop;

and I know the table exist. P.S. the table name $storeShop is dynamic, so it could be any name that user chooses and it will be created in the mysql database.

I hope I explained it good enough for someone to be able to help me.

Could someone please tell me why I get the mentioned error and how to solve it?

I suspect this is caused by smarty as I never used to get this error before I started using smarty.

Thanks in advance.

Это было полезно?

Решение

You are not parsing your string that contains the PHP variable.

$sql .= 'FROM $storeShop ';

To PHP single-quoted stings ' ' are literally what you have between the quotes.

" " Double quoted string will be Interpreted by PHP.

Try this:

$sql .= "FROM $storeShop ";  // OR
$sql .= 'From '. $storeShop .' ';

PHP Strings

Другие советы

mis been a long time since i used smarty but from what i remeber there is no such thoing as:

{$storeShop[$storeShop].id}

you could use however:{$storeShop.$another_storeShop.id} if $storeshop is like array('storeshop_key'=>array('id'->'id'))

also $smarty->assign('$storeShop', $value); will create variable $$storeShop which is not correct

tips: print arrays in php before sending to smarty var_dump($value) and then in smarty use {$storeShop|@print_r} to make sure everything is right

just remove

$smarty->assign('$storeShop', $value);

from your PHP code

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