As far as I'm aware you have to construct it yourself. Not that you were asking how to construct it, but for those who are wondering:
var url = $location.absUrl().split('?')[0]
Вопрос
If my URL is http://www.something.com/foo/bar/index.html?color=yellow&animal=rat
, it seems as though:
$location.path()
will return foo/bar/index.html
$location.absUrl()
will return http://www.something.com/foo/bar/index.html?color=yellow&animal=rat
$location.url()
will return foo/bar/index.html?color=yellow&animal=rat
Is there any function which will return http://www.something.com/foo/bar/index.html
?
Or do I have to construct that myself with functions like protcol, host, port, etc. (or strip the query params off myself)?
Решение
As far as I'm aware you have to construct it yourself. Not that you were asking how to construct it, but for those who are wondering:
var url = $location.absUrl().split('?')[0]
Другие советы
Not that this eliminates the need to construct it by yourself, just another way to do the same. If you use window.location object, you can just say window.location.origin+window.location.pathname
window.location object has
host:"localhost.abc.com:8080"
hostname:"localhost.abc.com"
href:"http://localhost.abc.com:8080/quickpick/repossessions/?displayStr=Repossessions&from=%2F&page=1"(whole url)
origin:"http://localhost.abc.com:8080"
pathname:"/quickpick/repossessions/"
port:"8080"
protocol:"http:"