It is the escape sequence. It tells interpreter to decipher it an an " instead of end to string. This might help http://docs.oracle.com/javase/tutorial/java/data/characters.html
what does SomeString.equals("\"D")) means?
Вопрос
I would like know how the following scenario works.
String test = "a,b,c";
String testary[] = test.split(",");
if(!testary[0].equals("\"D"))
gives?
I want to know why we are using backslash along with some char and how does the above statement works.
Решение 2
Другие советы
When you're writing a string literal, you put it in double quotes ("
). If you want to put an actual "
character in the string, you have to put a backslash (\
) before it so the parser knows that it's part of the string, not the ending quote. This is called "escaping" the quote character.
So the line
if(!testary[0].equals("\"D"))
tests whether the string at index 0 of the testary
array does not equal the string "D
(a double quote followed by the capital letter D). (The "not" part of that is the !
at the beginning.)
with the \
you are actually escaping the "
that is just after the \
, so equals will test against "D