Вопрос

I have a problem with the lapply function and I did not find any matching question posted earlier. I need to apply a permutation test to all list elements, however I am not able to setup the lapply correctly.

I am trying this

testperm <- lapply(test-list, FUN=perm.test, formula=(cover ~ group))

the function perm.test is from the package 'exactRankTests' cover is the dependent (numerical) variable and group is a factor.

Any hints on how to apply such a function would be very much appreciated. jens

Это было полезно?

Решение

When you use a formula, you often also need to supply a value to a data argument so the function knows which data to use. You data sets will be the list elements, so you need to use an anonymous function to supply them to perm.test.

In this case try:

testperm <- lapply(test.list, FUN=function(x) perm.test(formula=(cover ~ group),data=x)) 

Другие советы

It's your third argument that you need to take a look at.

lapply takes (at least) two arguments, a list (incl. data frame) and a function, FUN, that operates on it:

data(iris)
df0 = iris[1:5,1:3]

fnx = function(v){v^2}

lapply(df0, fnx)

lapply accepts an optional third argument which must correspond to additional arguments required by FUN and not furnished by lapply's first argument data structure:

lapply( df0[,1], quantile, probs=1:3/4)
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