How to generate a `kwargs` list?
-
20-01-2021 - |
Вопрос
From an external file I generate the following dictionary:
mydict = { 'foo' : 123, 'bar' : 456 }
Given a function that takes a **kwargs
argument, how can generate the keyword-args from that dictionary?
Решение
def foo(**kwargs):
pass
foo(**{ 'foo' : 123, 'bar' : 456 })
Не связан с StackOverflow