stored procedure for inserting comma seperated values in table using ms sql?
-
19-06-2021 - |
Вопрос
I have a table named assignRole.
I am passing string of userid (int) csv ,and passing roleid(int).
I want a stored procedure which split userid from string and take roleid and insert these values in table.this thing is to happen for all values in userid string.
Решение
First, create a function:
CREATE FUNCTION [dbo].[SplitInts]
(
@List VARCHAR(MAX),
@Delimiter CHAR(1)
)
RETURNS TABLE
WITH SCHEMABINDING
AS
RETURN ( SELECT Item = CONVERT(INT, Item) FROM (
SELECT Item = x.i.value('(./text())[1]', 'int') FROM (
SELECT [XML] = CONVERT(XML, '<i>' + REPLACE(@List, @Delimiter, '</i><i>')
+ '</i>').query('.') ) AS a CROSS APPLY [XML].nodes('i') AS x(i)) AS y
WHERE Item IS NOT NULL
);
Now you can say:
INSERT dbo.assignRole(RoleID, UserID)
SELECT @RoleID, Item
FROM dbo.SplitInts(@UserIDList, ',');
Другие советы
I like to use a table-valued function to do the split.
IF OBJECT_ID (N'dbo.StrSplit') IS NOT NULL DROP FUNCTION dbo.[StrSplit] GO
CREATE FUNCTION [dbo].[StrSplit] ( @String VARCHAR(MAX), @Delimiter char(1) ) RETURNS @Results TABLE ( Items NVARCHAR(MAX) ) AS BEGIN DECLARE @INDEX INT DECLARE @SLICE nvarchar(MAX)
-- HAVE TO SET TO 1 SO IT DOESNT EQUAL ZERO FIRST TIME IN LOOP
SELECT @INDEX = 1
-- Early exit if passed string is null
IF @String IS NULL RETURN
WHILE @INDEX !=0
BEGIN
-- GET THE INDEX OF THE FIRST OCCURENCE OF THE SPLIT CHARACTER
SELECT @INDEX = CHARINDEX(@Delimiter,@STRING)
-- NOW PUSH EVERYTHING TO THE LEFT OF IT INTO THE SLICE VARIABLE
IF @INDEX !=0
SELECT @SLICE = LEFT(@STRING,@INDEX - 1)
ELSE
SELECT @SLICE = @STRING
-- PUT THE ITEM INTO THE RESULTS SET
INSERT INTO @Results(Items) VALUES(@SLICE)
-- CHOP THE ITEM REMOVED OFF THE MAIN STRING
SELECT @STRING = RIGHT(@STRING,LEN(@STRING) - @INDEX)
-- BREAK OUT IF WE ARE DONE
IF LEN(@STRING) = 0 BREAK
END
RETURN
END
GO GRANT SELECT ON [dbo].[StrSplit] TO [public]
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