Launching a file using Process.Start works, but adding conditions does not

Question

So I am trying to launch a printer script using cscript from C#, and cscript launches a visual basic file. So sort of a daisy chain (and I want to keep this daisy chain intact for certain reasons).

Here's the code:

Process.Start("c:/windows/system32/cscript.exe c:/windows/System32/Printing_Admin_Scripts/en-US/prnport.vbs");

Now, when I launch ONLY cscript, no problems.

However when I add the condition of prnport.vbs to the cscript launch, I get this error in Visual Studio:

"The system cannot find the file specified"

But I can confirm the file path is correct - prnport.vbs DOES exist in /en-US.

So what am I doing wrong here? Can you not pass arguments (and in this case, the file path is being passed as an argument to cscript.exe) when using Process.Start?

New to C# and confused about the proper way to do this.

Answer 1

You have to specify the arguments separately from the file to run. Try the Process.Start(string, string) overload:

Process.Start("c:/windows/system32/cscript.exe", 
    "c:/windows/System32/Printing_Admin_Scripts/en-US/prnport.vbs");

Answer 2

That's an Argument, you'll need to use another overload of Process.Start

Have a look at the method's documentation.

Process.Start (String, String) will do, others are possible and offer more flexibility, if you should need that, too.

Answer 3

The Process.Start expects the file name as the first parameter. The arguments are given in separate argument.