ajax scroll position

Question

i been implamenting a piece of code in my website that iv found trough phpacademy.org tutorials the tutorial is 'how to create a like button'. iv got the button to work o.k, but i need an extra bit on function. the problem is that when i click the like button the page pops back up to the top

function like_add(id){
$.post('like_add.php', {id:id}, function(data){
    if(data == 'success'){
        like_get(id);
    } else {
        alert(data);
    }
});
function like_get(id){
$.post('like_get.php', {id:id}, function(data){
    $('#article_'+id+'_likes').text(data);
});
function delete_like(id){
$.post('delete_like.php', {id:id}, function(data){
    if(data == 'success'){
        like_get(id);
    } else {
        alert(data);
    }
});
}

is there anything i can apply to this script to save the scroll position???...i have applied save scroll position to links on my website but i cant figure out this:(

cheers

Answer 1

You can use the following to find the current page scroll position.

var scrollPosition = $(document).scrollTop(); 

That will return the current scroll position of the page.