You can just swap the bytes manually like this:
with open("file.bin", "rb") as infile, open("reversed", "wb") as outfile:
data = infile.read()
for i in xrange(len(data) / 2):
outfile.write(data[i*2+1])
outfile.write(data[i*2])
Вопрос
I have a .bin
file, and I want to simply byte reverse the hex data. Say for instance @ 0x10
it reads AD DE DE C0
, want it to read DE AD C0 DE
.
I know there is a simple way to do this, but I am am beginner and just learning python and am trying to make a few simple programs to help me through my daily tasks. I would like to convert the whole file this way, not just 0x10
.
I will be converting at start offset 0x000000
and blocksize/length is 1000000.
EDIT:
here is my code, maybe you can tell me where i am messing up.
def main():
infile = open("file.bin", "rb")
new_pos = int("0x000000", 16)
chunk = int("1000000", 16)
data = infile.read(chunk)
save(data)
def save(data):
with open("reversed", "wb") as outfile:
outfile.write(data)
main()
how would i go about coding it to byte reverse from CDAB TO ABCD? if it helps any the file is exactly 16MB
Решение
You can just swap the bytes manually like this:
with open("file.bin", "rb") as infile, open("reversed", "wb") as outfile:
data = infile.read()
for i in xrange(len(data) / 2):
outfile.write(data[i*2+1])
outfile.write(data[i*2])